Nolan Randall



548th place
(5-2-2)
Round | Opponent | Deck | Record | ||
---|---|---|---|---|---|
9 | Loss | Stephen Lowe | ![]() | ![]() | 7 - 3 - 3 |
8 | Win | Ruben Pereira | ![]() | ![]() | 4 - 2 - 2 |
7 | Win | Borja Álvarez Rodríguez | ![]() | ![]() ![]() | 3 - 3 - 2 |
6 | Win | Tsz chun Christopher Chan | ![]() | ![]() ![]() | 5 - 2 - 2 |
5 | Tie | Christian Jahrbacher | ![]() | ![]() | 2 - 2 - 2 |
4 | Tie | Daniele Sergio del Rosso | ![]() | ![]() | 4 - 4 - 1 |
3 | Loss | Pascal Tillenberg | ![]() | ![]() | 4 - 5 - 0 |
2 | Win | Paul Tesnow | ![]() | ![]() | 2 - 7 - 0 |
1 | Win | Jimmy O'Brien | ![]() | ![]() | 4 - 3 - 1 |