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Nolan Randall


548th place
(5-2-2)
| Round | Opponent | Deck | Record | ||
|---|---|---|---|---|---|
| 9 | Loss | Stephen Lowe | ![]() | ![]() | 7 - 3 - 3 |
| 8 | Win | Ruben Pereira | ![]() | ![]() | 4 - 2 - 2 |
| 7 | Win | Borja Álvarez Rodríguez | ![]() | ![]() ![]() | 3 - 3 - 2 |
| 6 | Win | Tsz chun Christopher Chan | ![]() | ![]() ![]() | 5 - 2 - 2 |
| 5 | Tie | Christian Jahrbacher | ![]() | ![]() | 2 - 2 - 2 |
| 4 | Tie | Daniele Sergio del Rosso | ![]() | ![]() | 4 - 4 - 1 |
| 3 | Loss | Pascal Tillenberg | ![]() | ![]() | 4 - 5 - 0 |
| 2 | Win | Paul Tesnow | ![]() | ![]() | 2 - 7 - 0 |
| 1 | Win | Jimmy O'Brien | ![]() | ![]() | 4 - 3 - 1 |













